最佳答案
这个代码可能实现打算器功能
#include "stdafx.h"
#include<iostream>
#include<stdio.h>
using namespace std;
void add()
{
printf("输入要打算的加数（比方a b）\n");
int adda=0, addb=0,addc=0;
cin >> adda;
cin >> addb;
addc = adda+addb;
cout <<adda<<"加"<<addb<< "等于" << addc << endl;
}
void substraction()
{
printf("输入要打算的减数（比方a b）\n");
int suba = 0, subb = 0, subc = 0;
cin >> suba;
cin >> subb;
subc = suba-subb;
cout <<suba<<"减"<<subb<< "等于" << subc << endl;
}
void multiplication()
{
printf("输入要打算的乘数（比方a b）\n");
int mula = 0, mulb = 0, mulc = 0;
cin >> mula;
cin >> mulb;
mulc = mula*mulb;
cout <<mula<<"乘"<<mulb<< "等于" << mulc << endl;
}
void division()
{
printf("输入要打算的除数（比方a b）\n");
int dsa = 0, dsb = 0, dsc = 0,dsd=0;
cin >> dsa;
cin >> dsb;
dsc = dsa/dsb;
dsd = dsa%dsb;
cout <<dsa<<"除"<<dsb<< "等于" << dsc <<"余"<<dsd<<endl;
}
void operation()//运算函数
{
printf("输入数据抉择做那种运算\n");
printf("输入0抉择退出，1做加法，2做减法，3做乘法，4做除法（保存余数）\n");
int operatione = 0;
cin >> operatione;
cout << endl;
try
{
if (operatione == 1)
{
//加法
add();
}
else if (operatione == 2)
{
//减法
substraction();
}
else if (operatione == 3)
{
//乘法
multiplication();
}
else if (operatione == 4)
{
//出发
division();
}
else if (operatione == 0)
{
exit(0);
}
else
{
throw 1;
}
}
catch (int i)
{
cout << "输入错误" << endl;
}
operation();
}
int main()
{
printf("欢送利用本打算器");
operation();
return 0;
}。