最佳答案
C言语作为一种历史长久且利用广泛的编程言语,是很多现代编程言语的基石。对初学者来说,经由过程经典的计划实例进修C言语,不只可能加深对基本不雅点的懂得,还能进步编程技能。以下是一些合适初学者的经典C言语计划实例:
1. 打算器顺序
目标:进修跟练习基本的C语言语法跟输入输出操纵。
代码示例:
#include <stdio.h>
int main() {
float num1, num2;
char operator;
printf("Enter an operator (+, -, *, /): ");
scanf("%c", &operator);
printf("Enter two operands: ");
scanf("%f %f", &num1, &num2);
switch(operator) {
case '+':
printf("%.1f + %.1f = %.1f", num1, num2, num1 + num2);
break;
case '-':
printf("%.1f - %.1f = %.1f", num1, num2, num1 - num2);
break;
case '*':
printf("%.1f * %.1f = %.1f", num1, num2, num1 * num2);
break;
case '/':
if(num2 != 0.0)
printf("%.1f / %.1f = %.1f", num1, num2, num1 / num2);
else
printf("Error! Division by zero.");
break;
default:
printf("Error! Invalid operator.");
}
return 0;
}
2. 字符串处理顺序
目标:进修字符串操纵,如复制、连接跟查找。
代码示例:
#include <stdio.h>
#include <string.h>
int main() {
char source[100], destination[100];
printf("Enter a string: ");
fgets(source, sizeof(source), stdin);
strcpy(destination, source); // 复制字符串
printf("Copied string: %s", destination);
strcat(destination, " appended"); // 连接字符串
printf("Concatenated string: %s", destination);
char search[20] = "appended";
if(strstr(destination, search) != NULL)
printf("The string '%s' was found in the destination string.\n", search);
else
printf("The string '%s' was not found in the destination string.\n", search);
return 0;
}
3. 阶乘打算
目标:练习轮回跟递归的利用,懂得递归函数的不雅点。
代码示例:
#include <stdio.h>
// 利用递归函数打算阶乘
long long factorial(int n) {
if (n <= 1)
return 1;
else
return n * factorial(n - 1);
}
int main() {
int num;
printf("Enter a positive integer: ");
scanf("%d", &num);
printf("Factorial of %d = %lld\n", num, factorial(num));
return 0;
}
4. 排序算法
目标:懂得并实现基本的排序算法,如冒泡排序。
代码示例:
#include <stdio.h>
void bubbleSort(int array[], int size) {
int i, j, temp;
for (i = 0; i < size-1; i++)
for (j = 0; j < size-i-1; j++)
if (array[j] > array[j+1]) {
temp = array[j];
array[j] = array[j+1];
array[j+1] = temp;
}
}
int main() {
int numbers[] = {64, 34, 25, 12, 22, 11, 90};
int n = sizeof(numbers)/sizeof(numbers[0]);
bubbleSort(numbers, n);
printf("Sorted array: \n");
for (int i=0; i < n; i++)
printf("%d ", numbers[i]);
printf("\n");
return 0;
}
这些实例可能帮助初学者逐步控制C言语的基本知识,并经由过程现实进步编程技能。跟着技能的晋升,可能实验更复杂的项目跟算法,进一步深刻懂得C言语的富强功能。