在C言语编程中,括号的利用无处不在,无论是把持流程、函数挪用还是数据构造,括号都扮演着至关重要的角色。正确地利用括号对编写可读、可保护的代码至关重要。本文将深刻探究C言语中括号的利用技能,特别是怎样高效且无误地实现括号检查。
( )
printf("Hello, World!");
。if (condition)
。{ }
struct Person { char name[50]; int age; };
。[ ]
int arr[10];
。int value = arr[5];
。栈是一种掉落队先出(LIFO)的数据构造,非常合实用于括号检查。以下是利用栈停止括号检查的步调:
以下是一个利用栈停止括号检查的C言语示例代码:
#include <stdio.h>
#include <stdlib.h>
typedef struct Stack {
char data;
int top;
int capacity;
} Stack;
Stack* createStack(int capacity) {
Stack* stack = (Stack*)malloc(sizeof(Stack));
stack->capacity = capacity;
stack->top = -1;
stack->data = (char*)malloc(stack->capacity * sizeof(char));
return stack;
}
int isFull(Stack* stack) {
return stack->top == stack->capacity - 1;
}
int isEmpty(Stack* stack) {
return stack->top == -1;
}
void push(Stack* stack, char item) {
if (isFull(stack))
return;
stack->data[++stack->top] = item;
}
char pop(Stack* stack) {
if (isEmpty(stack))
return '\0';
return stack->data[stack->top--];
}
int isMatchingPair(char character1, char character2) {
if (character1 == '(' && character2 == ')')
return 1;
else if (character1 == '{' && character2 == '}')
return 1;
else if (character1 == '[' && character2 == ']')
return 1;
return 0;
}
int isBalanced(char expression[]) {
Stack* stack = createStack(100);
for (int i = 0; i < strlen(expression); ++i) {
if (expression[i] == '(' || expression[i] == '{' || expression[i] == '[') {
push(stack, expression[i]);
} else if (expression[i] == ')' || expression[i] == '}' || expression[i] == ']') {
if (isEmpty(stack))
return 0;
char stackTop = pop(stack);
if (!isMatchingPair(stackTop, expression[i]))
return 0;
}
}
return isEmpty(stack);
}
int main() {
char expression[100];
printf("Enter an expression: ");
scanf("%[^\n]%*c", expression);
if (isBalanced(expression))
printf("The brackets are balanced.\n");
else
printf("The brackets are not balanced.\n");
return 0;
}
括号在C言语编程中扮演侧重要的角色。经由过程控制正确的括号利用技能跟括号检查方法,可能编写出愈加高效跟坚固的代码。利用栈数据构造是实现括号检查的有效方法,可能帮助开辟者疾速定位括号婚配错误,从而进步代码品质。