c 計算器源代碼

提問者:用戶FqJ8qlSw 發布時間: 2024-11-19 06:42:40 閱讀時間: 3分鐘

最佳答案

這個代碼可能實現打算器功能

#include "stdafx.h"

#include<iostream>

#include<stdio.h>

using namespace std;

void add()

{

printf("輸入要打算的加數(比方a b)\n");

int adda=0, addb=0,addc=0;

cin >> adda;

cin >> addb;

addc = adda+addb;

cout <<adda<<"加"<<addb<< "等於" << addc << endl;

}

void substraction()

{

printf("輸入要打算的減數(比方a b)\n");

int suba = 0, subb = 0, subc = 0;

cin >> suba;

cin >> subb;

subc = suba-subb;

cout <<suba<<"減"<<subb<< "等於" << subc << endl;

}

void multiplication()

{

printf("輸入要打算的乘數(比方a b)\n");

int mula = 0, mulb = 0, mulc = 0;

cin >> mula;

cin >> mulb;

mulc = mula*mulb;

cout <<mula<<"乘"<<mulb<< "等於" << mulc << endl;

}

void division()

{

printf("輸入要打算的除數(比方a b)\n");

int dsa = 0, dsb = 0, dsc = 0,dsd=0;

cin >> dsa;

cin >> dsb;

dsc = dsa/dsb;

dsd = dsa%dsb;

cout <<dsa<<"除"<<dsb<< "等於" << dsc <<"余"<<dsd<<endl;

}

void operation()//運算函數

{

printf("輸入數據抉擇做那種運算\n");

printf("輸入0抉擇退出,1做加法,2做減法,3做乘法,4做除法(保存餘數)\n");

int operatione = 0;

cin >> operatione;

cout << endl;

try

{

if (operatione == 1)

{

//加法

add();

}

else if (operatione == 2)

{

//減法

substraction();

}

else if (operatione == 3)

{

//乘法

multiplication();

}

else if (operatione == 4)

{

//出發

division();

}

else if (operatione == 0)

{

exit(0);

}

else

{

throw 1;

}

}

catch (int i)

{

cout << "輸入錯誤" << endl;

}

operation();

}

int main()

{

printf("歡送利用本打算器");

operation();

return 0;

}。

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